The ionisation constant of ammonia and ammonium hydroxide is same. If true write 1, else write 0.

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Solution

The ionisation constant of ammonia and ammonium hydroxide is same
$N H_{3} + H_{2} O \to N H_{4}^{+} + O H^{-} K_{1} \frac{[N H_{4}^{+}] [O H^{-}]}{N H_{3}}$
$N H_{4} O H \to N H_{4}^{+} + O H^{-} K_{2} = \frac{[N H_{4}^{+}] [O H^{-}]}{[N H_{4} O H]}$
But $[N H_{3}] = [N H_{4} O H]$ (this is because when ammonia is dissolved in water, it is converted to ammonium hydroxide).
Hence, $K_{1} = K_{2}$
Hence, the ionization constant of ammonia and ammonium hydroxide is same.

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