Question

The ionisation energy of 10 times ionised sodium atom (given the ionisation energy of H atom is 13.6eV) is

• A. $13.6eV$
• B. $13.6\times 11eV$
• C. $\frac{13.6}{11}eV$
• D. $13.6\times (11{)}^{2}eV$

Answer 1

The correct option is D $13.6\times (11{)}^{2}eV$

${\left(E_{ion}\right)}_{Na}=Z^2{\left(E_{ion}\right)}_H=(11{)}^{2}13.6eV$