The ionisation energy of a hydrogen like Bohr atom is $4$ Rydberg.
What is the wavelength of the radiation emitted when the electron jumps from the first excited state to the ground state?

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Solution

$∴ E_{I} = 4 R y d b e r g$
$E \propto \frac{1}{n^{2}}$
$E_{1} - E_{0} = [\frac{3}{4}] K J o u l e s$
$E = \frac{h c}{λ}$
$= \frac{3}{4} K = \frac{h c}{λ}$
$λ = \frac{h c 4}{3} K$

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The ionisation energy of a hydrogen like Bohr atom is 4 Rydberg.What is the wavelength of the radiation emitted when the electron jumps from the first excited state to the ground state?

∴EI=4RydbergE∝1n2E1−E0=[34]KJoulesE=hcλ=34K=hcλλ=hc43K

The ionisation energy of a hydrogen like Bohr atom is $4$ Rydberg.
What is the wavelength of the radiation emitted when the electron jumps from the first excited state to the ground state?

$∴ E_{I} = 4 R y d b e r g$
$E \propto \frac{1}{n^{2}}$
$E_{1} - E_{0} = [\frac{3}{4}] K J o u l e s$
$E = \frac{h c}{λ}$
$= \frac{3}{4} K = \frac{h c}{λ}$
$λ = \frac{h c 4}{3} K$