The ionisation energy of hydrogen atom is 13.6 ev. What will be the ionisation energy of ${L i}^{+ 2}$ ions?

13.6ev

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54.4ev

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122.4ev

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48.6ev

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Solution

The correct option is C
122.4ev

Ionisation energy = -(energy of the $1^{s t}$ orbit)
Energy of $1^{s t}$ orbit of ${L i}^{+ 2}$ = -13.6×9(Z for ${L i}^{+ 2}$ =3)
= -122.4ev

Ionisation energy of ${L i}^{+ 2}$ = -(-122.4) = 122.4ev

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