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Bohr's Postulates

The ionizatio...

Question

The ionization energy of ${L i}^{2 +}$ is equal to

9 h c R

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6 h c R

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2 h c R

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h c R

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Solution

The correct option is A $9 h c R$
Ionization energy of an atom $= h c R Z^{2}$
where $R$ is the Rydberg constant and $Z$ is the atomic number.
We know, $Z = 3$ for ${L i}^{2 +}$
Ionization energy of $L i^{2 +}$ $= {(3)}^{2} h c R$ $= 9 h c R$

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