The correct option is B 49.5 J
Given, mass of Na atoms = 2.3 mg = 2.3×10−3 g
So, number of moles of Na = 2.3×10−323=10−4 mol
Energy involved in ionization of 1 mole of Na atom is =495 kJ/mol
So, energy involved in ionization of 10−4 mol Na atom is: = 495×103×10−4 J = 49.5 J