Question

The ionization energy of the ionized sodium atom $N{a}^{10+}$ is

• A. $13.6eV$
• B. $13.6\times 11eV$
• C. $\left(13.6/11\right)eV$
• D. $13.6\times \left({11}^2\right)eV$

Answer 1

The correct option is D $13.6\times \left({11}^2\right)eV$

Hydrogen like atom $N{a}^{10+}$
Ionisation energy = Energy to remove the electron
$(n=1)\to (n=\infty )$
From Formula attached
$E_{ionisation}=13.6\left(11{)}^2\right(1-0)=13.6(11{)}^{2}eV$