Question

The ionization isomer of $\left[Cr\right(H_{2}O{)}_{4}Cl\left(N{O}_2\right)]Cl$ is

• A. $\left[Cr\right(H_{2}O{)}_4\left(O_{2}N\right)]C{l}_2$
• B. $\left[Cr\right(H_{2}O\left)C{l}_2\right]N{O}_2$
• C. $\left[Cr\right(H_{2}O{)}_{4}Cl\left(ONO\right)]Cl$
• D. $\left[Cr\right(H_{2}O{)}_{3}C{l}_2\left(N{O}_2\right)]H_{2}O$

Answer 1

The correct option is B $\left[Cr\right(H_{2}O\left)C{l}_2\right]N{O}_2$

$C{l}^{-}$ is replaced by $N{O}_2^{-}$ in ionization sphere and are ionization isomers.