The ionization potential $(I_{1})$ of nitrogen ( $Z = 7$ ) is more than oxygen ( $Z = 8$ ). This is explained by :

Hunds rule

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Excitation rule

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Pauli principle

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Aufbau principle

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Solution

The correct option is A Hunds rule
According to Hund's rule the electrons will be filled in orbitals such that they have parallel spin first and after that pairing will occur. Therefore, N has half filled orbital which has extra stability. Due to this stability I.P of N > O.

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| z - 1 - i | = \sqrt{2}

| z + 1 + i | = 2

The first ionization potential in electron volts of nitrogen and oxygen atoms respectively are given by

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