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1900's Physics and Wave

The ionizatio...

Question

The ionization potential of a hydrogen atom is 13.6 eV. The ionization potential of $B e^{3 +}$ ion is:

A

217.6 e V

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B

109.8 e V

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C

54.4 e V

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D

136.0 e V

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Solution

The correct option is A $217.6 e V$
$E_{n} = E_{0} \times \frac{z^{2}}{n^{2}}$ , where $n = 1, E_{o} = 13.6, Z = 4$ .

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