1
Question
The ionization potential of the hydrogen atom is 13.6 eV. Its energy in n = 2 energy state is
The ionization potential of the hydrogen atom is 13.6 eV. Its energy in n = 2 energy state is
Open in App
Solution
The correct option is A -3.4 eV
Energy of the electron in the first orbit of the atom, E1=−13.6 eV
Its energy in the second orbit, E2=−13.6 eV(2)2=−3.4 eV
Hence, the correct choice is (a).
Energy of the electron in the first orbit of the atom, E1=−13.6 eV
Its energy in the second orbit, E2=−13.6 eV(2)2=−3.4 eV
Hence, the correct choice is (a).
Suggest Corrections
0
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
