Question

The ionization potential of the hydrogen atom is $13.6\text{volt}$. The energy required to remove an electron from the second orbit of hydrogen is:

• A. $3.4\text{eV}$
• B. $6.8\text{eV}$
• C. $13.6\text{eV}$
• D. $27.2\text{eV}$

Answer 1

The correct option is A $3.4\text{eV}$

$\because$ Ionization energy is given by
$E_1=E_{\infty }-E_n$
$=0-(-13.6\frac{z^2}{n^2})$
$=13.6\frac{z^2}{n^2}$
For hydrogen atom, required energy to remove electron from second orbit :
$E_i=13.6\times \frac{1^2}{2^2}=\frac{13.6}{4}\text{eV}$
$E_i=3.4\text{eV}$