The iron door of a building is $3 m$ broad. It can be opened by applying a force of $100 N$ normally at the middle of the door. Calculate the torque applied on the door.

100 N m

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150 N m

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200 N m

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300 N m

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Solution

The correct option is B $150 N m$
Given,
Breadth of the door (B) $= 3 m$ .
Force applied on the door (F) $= 100 N$ .
Since force is applied at the middle of the door
So,
Distance of point of application of force $= \frac{B}{2} = \frac{3}{2} = 1.5 m$ .
Moment of force applied on the open the door $= 100 N \times 1.5 m . = 150 N m$ .
Thus, $150 N m$ torque is applied to open the door.

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The iron door of a building is 3 m broad. It can be opened by applying a force of 100 N normally at the middle of the door. Calculate the torque applied on the door.

The iron door of a building is $3 m$ broad. It can be opened by applying a force of $100 N$ normally at the middle of the door. Calculate the torque applied on the door.