Question

The iso neutronic triad of nuclei is

• A. ${}_6{C}^{14}$, ${}_7{N}^{14}$, ${}_9{F}^{17}$
• B. ${}_6{C}^{14}$, ${}_7{N}^{14}$, ${}_9{F}^{19}$
• C. ${}_6{C}^{14}$, ${}_7{N}^{15}$, ${}_9{F}^{17}$
• D. ${}_6{C}^{12}$, ${}_7{N}^{14}$, ${}_9{F}^{19}$

Answer 1

Answer: (C)

${}_6{C}^{14}$, ${}_7{N}^{15}$, ${}_9{F}^{17}$

The number of neutrons in ${}_6{C}^{14}$, ${}_7{N}^{15}$ and ${}_9{F}^{17}$ are same and equal to $8$.