Question

The isomer(s) of $\left[Co\right(N{H}_3{)}_{4}C{l}_2]$ that has/have a $Cl-Co-Cl$ angle of ${90}^o$, is/are :

• A. trans only
• B. meridional and trans
• C. cis and trans
• D. cis only

Answer 1

Answer: (D)

cis only

Given compound is $\left[CO\right(N{H}_3{)}_{4}C{l}_2]$

For this compound two different forms are possible namely cis and trans.

So, in cis isomer two $Cl$ are at ${90}^o$ angle with each others. while in trans two $Cl$ are ${180}^o$ angle with each other.

Since, $Cl-Co-Cl$ is asked in which case it is ${90}^o$

Hence, option D is correct.