The IUPAC name for the coordination compound $B a {[B r F_{4}]}_{2}$ is:

barium tetrafluorobromate (V)

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barium tetrafluorobromate (III)

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barium bis(tetrafluorobromate) (III)

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none of these

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Solution

The correct option is B barium tetrafluorobromate (III)
$B a [B r F_{4}] \to B a^{+ 2} + B r F_{4}^{- 1}$
As each fluoride contains $- 1$ charge, so $B r$ is in $+ 3$ oxidation state.
So, the name of complex is barium tetrafluorobromate(III).

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