Question

The IUPAC name for the coordination compound $Ba{\left[Br{F}_4\right]}_2$ is:

• A. barium tetrafluorobromate (V)
• B. barium tetrafluorobromate (III)
• C. barium bis(tetrafluorobromate) (III)
• D. none of these

Answer 1

The correct option is B barium tetrafluorobromate (III)

$Ba\left[Br{F}_4\right]\to B{a}^{+2}+Br{F}_4^{-1}$
As each fluoride contains $-1$ charge, so $Br$ is in $+3$ oxidation state.
So, the name of complex is barium tetrafluorobromate(III).