Question

The IUPAC name of $C{H}_3-C\left(Cl\right)=C\left(C{H}_3\right)-CH\left(C_2{H}_5\right)-C{H}_2-C\equiv CH$ is:

• A. 6-chloro-4-ethyl-5-methylhept-5-en-1-yne
• B. 6-chloro-4-ethyl-5-methylhept-1-yn-5-ene
• C. 2-chloro-4-ethyl-3-methylhept-2-yn-6-ene
• D. 2-chloro-4-ethyl-3-methylhept-6-yn-2-ene

Answer 1

Answer: (A)

6-chloro-4-ethyl-5-methylhept-5-en-1-yne

Here there are 7 carbons. So it is heptane. Chlorine is in 6th position and triple bond should be given the highest preference so it is given 1st position and double bond is given the next priority.

So, the IUPAC name is 6-chloro-4-ethyl-5-methylhept-5-en-1-yne.