Question

The IUPAC name of $C{H}_3-CO-CHCl-C{H}_2-COOH$ is

• A. 3-Chloro -4-oxopentanoic acid
• B. 4- oxo -3 -Chloropentanoic acid
• C. 2- oxo-3- Chloropentanoic acid
• D. 1- carboxy - 3 Chloro-4- Ketobutane

Answer 1

The correct option is A

3-Chloro -4-oxopentanoic acid

$\stackrel{5}{C{H}_3}-\stackrel{O}{\stackrel{||}{\stackrel{4}{C}}}-\underset{Cl}{\underset{|}{\stackrel{3}{CH}}}-\stackrel{2}{C{H}_2}-\stackrel{1}{COOH}$ Carboxylic acid is given priority over other functional Groups. Ketone is secondary functional group so prefix oxo is used. The substituants cblorise in position 3, Ketine in position 4 are written in alphabetical order.