The IUPAC name of $[P t (N H_{3})_{4} (N O_{2}) C l] S O_{_{4}}$ is :

tetramminechloronitroplatinum (II) sulphate

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tetramminechloronitroplatinum (IV) sulphate

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chlorotetramminenitroplatinum (IV) sulphate

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chloronitrotetrammineplatinum (IV) sulphate

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Solution

The correct option is B tetramminechloronitroplatinum (IV) sulphate
Given the compound, $[P t (N H_{3})_{4} (N O_{2}) C l] S O_{4}$ .
Here, we know $S O_{4}$ has $- 2$ charge.
So, the overall charge on $P t (N H_{3})_{4} (N O_{2}) C l]$ is $+ 2$ . $C l$ and $N O_{2}$ has $- 1$ valency each.
Therefore, charge on $P t$ has to be $+ 4$ to balance the overall charge.
Therefore, the IUPAC name of $[P t (N H_{3})_{4} (N O_{2}) C l] S O_{_{4}}$ is tetramminechloronitroplatinum (IV) sulphate.

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[P t (N H_{3})_{2} C l_{2}]

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