Question

The IUPAC name of the compound $HC\equiv CH-CH=CH-C{H}_3$ is pent-2-en-4-yne.

• A. True
• B. False

Answer 1

The correct option is B False

$HC\equiv CH-CH=CH-C{H}_3$

In this compound, on counting from the left, the triple bond comes between first and second carbon and double bond comes between third and fourth carbon atom.

Here since the triple bond is the lowest locant, it will be given preference.

Thus IUPAC name of the compound will be: Pent-3-en-1-yne