The IUPAC name of the compound

is

3 - keto - 2 - methylhex - 4 - enal

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5 - formylhex - 2 - en - 3 - one

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5 - methyl - 4 - oxohex - 2 - en - 5 - al

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3 - keto - 2 - methylhex - 5 - enal

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Solution

The correct option is A
3 - keto - 2 - methylhex - 4 - enal

- CHO group gets higher priority over >C = 0 and

group in numbering of principal carbon chain.

IUPAC name = 3 - keto - 2 - methylhex - 4 - enal.

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Similar questions

Structure of the compound whose IUPAC name is 3-Ethyl-2-hydroxy-4-methylhex-3-en-5-ynoic acid is:

3-ethynyl-2-hydroxy-4-methylhex-3-en-5-ynoic

2-(Cycloprop-2-enyl)-5-methyl hex - 1- ene

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