Question

The IUPAC name of the compound is:

$H_2=CH-\underset{\underset{C{H}_3}{|}}{C}H-\underset{\underset{C_2{H}_5}{|}}{C}H-\underset{\underset{OH}{|}}{C}H-C{H}_3$

Answer 1

The IUPAC name of the structure is 3-ethyl-4-methylhex-5-en-2-ol.
Here, the long chain consists of 6 carbon atoms with an $-OH$ group at C-2, $-C_2{H}_5$ group at C-3, $-C{H}_3$ group at C-4 and a double bond at C-5.