Question

The IUPAC name of the compound

• A. 1-Ethylpropanamide
• B. N-Ethylpropanamide
• C. N-Butylpropanamide
• D. N-Ethylbutanamide

Answer 1

The correct option is D

N-Ethylbutanamide

First let us try to find out the primary functional group. There seems to be a chain of 6 carbon atoms. A closer look reveals that on either side of

are 4 carbon atoms to the left and 2 carbon atoms to the right.

We know that $-\stackrel{O}{\stackrel{||}{C}}-N{H}_2$ is the amide group.

Here one of the Hydrogens in the

$-\stackrel{O}{\stackrel{||}{C}}-\stackrel{..}{\underset{H}{\underset{|}{N}}}-H$

is substituted by an Ethyl group $(-C{H}_{2}C{H}_3)$.

So the parent chain (with the primary functional group) contains 4 carbon atoms.

word root = But

primary suffix = ane (only C-C single bonds are there)

secondary suffix = amide

secondary prefix = N-ethyl {This because the Ethyl group is directly attached to Nitrogen atom}

Hence the IUPAC name is

(D) N - Ethylbutanamide