Question

The IUPAC name of the compound.

$\underset{.}{\underset{OH}{\underset{|}{C}}{H}_2-\underset{N{H}_2}{\underset{|}{C}}H-COOH}$

• A. $2$-amino-$3$-hydroxy propanoic acid
• B. $1$-hydroxy-$2$-amino propan-$3$-oic acid
• C. $1$-amino-$2$-hydroxy propanoic acid
• D. $3$-hydroxy-$2$-amino propanoic acid

Answer 1

The correct option is A $2$-amino-$3$-hydroxy propanoic acid

The IUPAC name of the compound $\underset{.}{\stackrel{3}{\underset{OH}{\underset{|}{C}}}{H}_2-\stackrel{2}{\underset{N{H}_2}{\underset{|}{C}}}H-\stackrel{1}{C}OOH}$ is $2$-amino-$3$-hydroxyl propanoic acid.
$-COOH$ group gets preference over $-OH$ and $-N{H}_2$ groups. Hence, the parent compound is propanoic acid, a carboxylic acid with 3 C atoms. The numbering is started from C atom of $-COOH$ group. The names of substituents are written in alphabetical order.