The IUPAC name of the following compound is 2 - methylbicyclo [3.1.1] heptane.

True

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False

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Solution

The correct option is A True
In $b i c y c l o$ compounds, the numbering is started with the ring having more number of carbon atoms.
Accordingly, the numbering of given compound will be as given in the question.
Also, in the IUPAC name, the name $b i c y c l o$ is followed by number of carbon atoms between two fixed carbon atoms, in ascending order. The bridge-head carbon atom is also considered.
Therefore, the IUPAC name of given compound will be $2 - m e t h y l - b i c y c l o [3, 1, 1] h e p t a n e$

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