The IUPAC name of the following compound is?
CH3−CH2−CH2−C|HCH3−CH2−CH3|CH−CH3
2,4-Dimethylheptane
Our first step should be to choose the longest chain from the given alkane.
Although there are 9 carbon atoms in total, the longest chain contains only 7 carbon atoms.
Primary suffix = ane
Word root = hept
If we number the chain, as shown above, the two methyl substituents are at C4 and C6
Now, let's look at another case.
Now we have substituents at C2 and C4. In both cases, there are exactly two substituents.
We choose the numbering direction that gives the lowest set of locants.
Hence, secondary prefix = 2,4-dimethyl (since there are two methyl groups-one each at C2 and C4
Hence, the IUPAC name is 2,4-Dimethylheptane