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B
4- methyl-1-pentene
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C
1-hexene
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D
3- methylpentene
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Solution
The correct option is C 4- methyl-1-pentene
5CH3−4C|HCH3−3CH2−2CH=1CH2
since it contains double bond hence it is alkene and it also has methyl group attached to the fourth carbon atom, Thus its IUPAC name of the compound will be: