The IUPAC name of the following is:
$C H_{3} C H = C H - C H_{2} - C H (N H_{2}) - C H_{2} C O O H$

3-Aminohept-5-enoic acid

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5-Aminohex-2-ene carboxylic acid

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3-Aminohept-4-enoic acid

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5-Aminohept-2-enoic acid

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Solution

The correct option is A 3-Aminohept-5-enoic acid
By IUPAC rules,
Principle functional group must be included in the longest continuous carbon chain. Thus, carboxylic acid group should be in the carbon chain while numbering.
$- C O O H$ is higher in priority than $- N H_{2}$
Suffix used for -COOH group is -oic acid.
Prefix used for $- N H_{2}$ is amino
Also double bond is present at 5th position.
Since longest carbon chain is of 7 carbon so word root is hept. Hence, IUPAC name is 3-Aminohept-5-enoic acid.

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