The IUPAC name of the given compound is 4, 5-diethyl-7-methyldecane.
True
step:Identity the longest chain.
⇒10 carbon atom chain ⇒ward root=dec
Given compound is alkane ⇒primary suffix=ane
We can number the chain in 2 ways.
Step 2:number the carbon atoms in the chain to give the lowest set of locants to the three substituents.
Right numbering gives locant= {4,5,7}
Wrong (reverse) numbering yeilds={4,6,7}
Secondary prefix=4, 5-diethyl-7-methyl
Hence the IUPAC name is:
4,5-Diethyl-7-methyldecane
Answer is TRUE
In the secondary prefix, alphabetically ethyl precedes methyl. we do not consider 'd' in diethyl'.
Words like 'di' 'tri' etc .are ignored.