The IUPAC name of Xe[PtF6] (with oxidation state).Explain how the oxidation state came.

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Solution

Dear student,

The IUPAC name is xenon hexafluoroplatinate(V)
For the calculation of oxidation state of Pt.
This exists in the form of the ion as $[P t F_{6}]^{- 1}$
The oxidation of fluorine is -1
Let the oxidation state of Pt is x
Therefore,
x + 6 (-1) = -1
x -6 = -1
x = -1 + 6 = 5

The oxidation state comes out to be +5 or written as (V)

Regards

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