The Jog falls in Karnataka states are nearly 20 m high. 2000 tons (1 ton = 1,000 kg) of water fall from it in a minute. Calculate the equivalent power if all this energy can be utilized ? Take g = 10 m/s².

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Solution

Dear Student ,
The power is ,
$P = \frac{m g h}{t} = \frac{1000 \times 2000 \times 10 \times 20}{60} = 6 \cdot 66 \times 10^{6} W$
Regards

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The Jog falls in Karnataka states are nearly 20 m high. 2000 tons (1 ton = 1,000 kg) of water fall from it in a minute. Calculate the equivalent power if all this energy can be utilized ? Take g = 10 m/s2.

Dear Student , The power is , P=mght=1000×2000×10×2060=6·66×106 W Regards

The Jog falls in Karnataka states are nearly 20 m high. 2000 tons (1 ton = 1,000 kg) of water fall from it in a minute. Calculate the equivalent power if all this energy can be utilized ? Take g = 10 m/s².

Dear Student ,
The power is ,
$P = \frac{m g h}{t} = \frac{1000 \times 2000 \times 10 \times 20}{60} = 6 \cdot 66 \times 10^{6} W$
Regards