The junction diode shown in figure is ideal. The current in the circuit is

50 A

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30 A

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20 m A

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30 m A

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Solution

The correct option is C $20 m A$
Let $I$ be the current in the circuit,
As the diode is ideal so voltage drop across the diode is $0$ since it is in forward bias.
$4 V - 100 I = 1 V$
$⟹ I = 0.02 m A = 20 m A$

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Assuming that the junction diode is ideal in the circuit shown in fig, the current through the diode is

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