wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The Ka of C6H5OH is 1.0×1010.What is the pH of a 0.10 M C6H5O solution?

A
10.51
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11.04
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
11.50
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 11.50
Kb=KwKa=1×10141.0×1010=1.0×104

For a base phenoxide ion, the expression for the pOH of the solution is given by the expression pOH=logKbC

Substitute values in the above expression:

pOH=log(1.0×104×0.10)=2.5

pH=14pOH=142.5=11.50

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hydrolysis
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon