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Characteristic Spectrum

The Kα x-ray ...

Question

The $K_{α}$ x-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atom with a K electron knocked out is 23.32 keV, what will be the energy of this atom when an L electron is knocked out? If required, take hc = 1242 eV.nm.

16.37 keV

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5.82 keV

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62.02 keV

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9.45 keV

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Solution

The correct option is B 5.82 keV
In our notation of energy levels, an energy $E_{X}$ will mean the energy of the atom when there's a missing electron in the Xshell ( X = K, L, M, N,....). Writing quantitatively.
$E (K_{α})$ = $E_{K} - E_{L}$
$\Rightarrow E_{L} = E_{K} - E (K_{α})$
$\Rightarrow E_{L} = E_{K} - (\frac{h c}{λ_{K α}})$
$\Rightarrow E_{L} = 23.32 k e V - (\frac{1242 e V . n m}{0.071 n m}) = 23.32 k e V - 17.5 e V$
$\Rightarrow E_{L} = 5.82 k e V .$

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The $K_{α}$ X-ray of molybdenum has wavelength 71 pm. If the energy of a molybdenum atom with a K electron knocked out is 23.32 keV, What will be the energy of this atom when an L electron is knocked out?

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The Kα x-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atom with a K electron knocked out is 23.32 keV, what will be the energy of this atom when an L electron is knocked out? If required, take hc = 1242 eV.nm.

The $K_{α}$ x-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atom with a K electron knocked out is 23.32 keV, what will be the energy of this atom when an L electron is knocked out? If required, take hc = 1242 eV.nm.