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Characteristic Spectrum

The K α X-ray...

Question

The $K_{α}$ X-ray of molybdenum has wavelength 71 pm. If the energy of a molybdenum atom with a K electron knocked out is 23.32 keV, What will be the energy of this atom when an L electron is knocked out?

23.32 keV

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5.82 keV

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13.2 keV

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17.5 keV

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Solution

The correct option is B
5.82 keV

$E_{K} - E_{L} = \frac{h c}{λ}$

$E_{L} = 23.32 - 17.5 = 5.82 k e V$ .

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Similar questions

K_{α}

k_{α}

X

0.071 nm

k

27.5 keV

L

(in keV)

[h = 4.14 \times 10^{- 15} eVs, c = 3 \times 10^{8} {ms}^{- 1}]

K_{a} - X

71 \times 10^{- 12} m

23.32 K e V

h c = 12.42 \times 10^{- 7} e V

Cell containing vacancy	K	L	M
Energy in keV	69.5	11.3	2.3

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