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Question

The Kc for the reaction A+BC is 4 and Kc for 2A+DC is 6 the value of Kc for C+D2B is:

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Solution

(i)A+BC
Kc1=[C][A][B]=4 (1)


(ii)2A+DC
Kc2=[C][A]2[D]=6 (2)


(iii)C+D2B
Kc3=[B]2[C][D] (3)

using equation (1),
[B]=[C]4[A]

put the value of [B] in equation (3)
Kc3=[C]216[A]2[C][D]=[C]16[A]2[D]

From equation (2)
Kc3=Kc216=616=38



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