wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The K.E of mole of an ideal gas is E=32 RT. Then Cp will be

A
0.5 R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.1 R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.5 R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.5 R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2.5 R
U=PE+KE

There won't be any potential energy as we do not consider force of interaction.

U=f21 RT f=3

CV=f2RCp=(f2+1)R

CV=32RCp=52R

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon