Question

The K.E. of one mole of an ideal gas is
$E=\left(3/2\right)RT,then{C}_p$ will be
A) 0.5R
B) 0.1R
C) 1.5R
D) 2.5R

Answer 1

The correct option is C

The kinetic energy or the total internal energy of one mole of gas is

$U=\left(\frac{3}{2}\right)RT$

if$C_v$ is molar specific heat at constant volume then

$C_v=\frac{dU}{dT}$

$\frac{3}{2}R$

Now for an ideal gas

$C_p-C_v=R$

$C_p$ molar specific heat capacity of constant pressure

$C_p=\left(\frac{3}{2}\right)R+R$

$\left(\frac{5}{2}\right)R$

$1.5R$