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Reaction Quotient

The Kp valu...

Question

The $K_{p}$ value for $2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)$ is $5.0 a t m^{- 1}$ .

If the equilibrium pressures of $S O_{2}$ and $S O_{3}$ are equal. What is the equilibrium pressure of $O_{2}$ ?

A

0.2 atm

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B

0.3 atm

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C

0.4 atm

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D

0.1 atm

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Solution

The correct option is A 0.2 atm
The given equation is , $2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)$

Thus, $K_{p} = \frac{P_{S O_{3}}^{2}}{P_{O_{2}} {P_{S O_{2}}}^{2}}$

But pressure of $S O_{2}$ and $S O_{3}$ are equal, thus

$K_{p} = \frac{1}{P_{O_{2}}}$

$=> P_{O_{2}} = 0.2 a t m$

So, the correct option is $A$

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