The K- X - ray emission line of tungsten occurs at - - 0-021nm- The energy difference between K and L levels in this atom is about

Energy difference, E_K E_L = hc/λ = 1241.5 eV.nm/0.021 nm = 59 keV ...

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Standard XI

Physics

Line Spectra

The K∝ X - ra...

Question

The $K_{\propto}$ X - ray emission line of tungsten occurs at $λ$ = 0.021nm. The energy difference between K and L levels in this atom is about

0.51 MeV

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1.2 MeV

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59 keV

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136 eV

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Solution

The correct option is C 59 keV
Energy difference, $E_{K} - E_{L} = \frac{h c}{λ} = \frac{1241.5 e V . n m}{0.021 n m} = 59 k e V$

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The K∝ X - ray emission line of tungsten occurs at λ = 0.021nm. The energy difference between K and L levels in this atom is about

The correct option is C 59 keVEnergy difference, EK−EL=hcλ=1241.5 eV.nm0.021 nm=59 keV

The $K_{\propto}$ X - ray emission line of tungsten occurs at $λ$ = 0.021nm. The energy difference between K and L levels in this atom is about

The correct option is C 59 keV
Energy difference, $E_{K} - E_{L} = \frac{h c}{λ} = \frac{1241.5 e V . n m}{0.021 n m} = 59 k e V$