The Ksp of Ag2CrO4 - 1-1- 10-10- what is the value of solubility- S-

The correct option is B 3.02× 10^ 4 The K_sp of Ag_2CrO_4 = 1.1× 10^ 10 . The value of solubility S is 3.02 × 10^ 3 M .The expressio ...

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Standard XII

Chemistry

Solubility Product

The Ksp of ...

Question

The $K_{s p}$ of $A g_{2} C r O_{4}$ = $1.1 \times 10^{- 10}$ , what is the value of solubility, $S$ ?

1.1 \times 10^{- 11}

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3.02 \times 10^{- 4}

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1.1 \times 10^{- 12}

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3.02 \times 10^{- 9}

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Solution

The correct option is B $3.02 \times 10^{- 4}$
The $K_{s p}$ of $A g_{2} C r O_{4} = 1.1 \times 10^{- 10}$ . The value of solubility $S$ is $3.02 \times 10^{- 3} M$ .
The expression for the solubility prouct is $K_{s p} = [A g^{+}]^{2} [C r O_{4}^{2 -}] = (2 S)^{2} S = 4 S^{3}$
Hence,

$S = (\frac{K_{s p}}{4})^{\frac{1}{3}} = (\frac{1.1 \times 10^{- 10}}{4})^{\frac{1}{3}} = 3.02 \times 10^{- 4}$

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Similar questions

The $K_{s p}$ of $A g_{2} C r O_{4}$ is $1.1 \times 10^{- 12}$ at 298K. The solubility (in mol/L) of $A g_{2} C r O_{4}$ in 0.1M $A g N O_{3}$ solution is:

Q. The

K_{s p} o f A g_{2} C r O_{4} i s 1.1 \times 10^{- 12} a t 298 K .

The solubility (in

m o l / L

) of

A g_{2} C r O_{4}

in a

0.1 M A g N O_{3}

solution is

Q. The

K_{s p}

A g_{2} C r O_{4}

1.1 \times 10^{- 12}

at 298 K. The solubility (in mole / L) of

A g_{2} C r O_{4}

in a

0.1 M A g N O_{3}

solution is

The

k_{s p}

A g_{2} C r O_{4}

1.1 \times 10^{- 12}

298 k

. The solubility (in mol/l) of

A g_{2} C r O_{4}

in a 0.1M

A g N O_{3}

solution is :

Q. The solubility product

(K_{s p})

of the following compounds are given at

25^{\circ} C

. The compound most soluble and least soluble coumpounds are:
Compounds

K_{s p}

A g C l 1.1 \times 10^{- 10} A g I 1.1 \times 10^{- 16} P b C r O_{4} 4.0 \times 10^{- 14} A g_{2} C O_{3} 8.0 \times 10^{- 12}

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The Ksp of Ag2CrO4 = 1.1×10−10, what is the value of solubility, S?

The correct option is B 3.02×10−4The Ksp of Ag2CrO4=1.1×10−10. The value of solubility S is 3.02×10−3 M.The expression for the solubility prouct is Ksp=[Ag+]2[CrO2−4]=(2S)2S=4S3 Hence, S=(Ksp4)13=(1.1×10−104)13=3.02×10−4

The $K_{s p}$ of $A g_{2} C r O_{4}$ = $1.1 \times 10^{- 10}$ , what is the value of solubility, $S$ ?