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Question

The Ksp of Ag2CrO4,AgCl,AgBr and AgI are respectively, 1.1×1012,1.8×1010,5.0×1013,8.3×1017. Which one of the following salts will precipitate last if AgNO3 solution is added to the solution containing equal moles of NaCl, NaBr, Nal and Na2CrO4?


A

Ag2CrO4

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B

AgI

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C

AgCl

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D

AgBr

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Solution

The correct option is A

Ag2CrO4


Let the concentration of NaCl, NaBr, NaI and Na2CrO4 be 1M.

Ksp(Ag2CrO4)=[Ag+]2[CrO24]=4s3 where s is the solubility and the concentartion of the chromate ion.

[Ag+]Ag2CrO4=Ksp(Ag2CrO4)[CrO24]=1.1×1012(1.1×1012/4)1/3

[Ag+]AgI=Ksp(AgI)[I]=8.3×10171

[Ag+]AgCl=Ksp(AgCl)[Cl]=1.8×10101

[Ag+]AgBr=Ksp(AgBr)[Br]=5.0×1013

Solubility of Ag2CrO4 is the highest it will precipitate last


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