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Question

The Ksp of FeS=4×1019at 298 K. The minimum concentration of H+ ions required to prevent the precipitation of FeS from a 0.01 M solution of Fe2+ salt by passing H2S (0.1 M)
(Given: ka1×kb1=1021) for H2S


A
1.2×104M
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B
1.6×103 M
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C
2.0×102 M
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D
2.5×104 M
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Solution

The correct option is B 1.6×103 M
Given:
Ksp(FeS)=4×1019, [FeS]=0.01 M, ka1×kb1=1021(H2S)
H2Ska1H++HSHSkb1H++S2FeSFe2++S2Ksp=[Fe2+][S2]=4×10194×1019=(0.01)[S2]1[S2]=4×1017 Mka1=[H+][HS]H2Skb1=[H+][S2][HS]ka1×kb1=[H+][HS][H2S]×[H+][S2][HS]1021=[H+]2[S2][H2S]1021=[H+]24×10170.1[H+]2=0.25×105[H+]2=2.5×106[H+]=2.5×106=1.58×103 M1.6×103 M

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