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Question

# The Ksp of FeS=4×10−19at 298 K. The minimum concentration of H+ ions required to prevent the precipitation of FeS from a 0.01 M solution of Fe2+ salt by passing H2S (0.1 M) (Given: ka1×kb1=10−21) for H2S

A
1.2×104M
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B
1.6×103 M
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C
2.0×102 M
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D
2.5×104 M
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Solution

## The correct option is B 1.6×10−3 MGiven: Ksp(FeS)=4×10−19, [FeS]=0.01 M, ka1×kb1=10−21(H2S) H2Ska1−−→H++HS−HS−kb1−−→H++S2−FeS→Fe2++S2−Ksp=[Fe2+][S2−]=4×10−19⇒4×10−19=(0.01)[S2−]1⇒[S2−]=4×10−17 Mka1=[H+][HS−]H2Skb1=[H+][S2−][HS−]ka1×kb1=[H+][HS−][H2S]×[H+][S2−][HS−]⇒10−21=[H+]2[S2−][H2S]⇒10−21=[H+]24×10−170.1⇒[H+]2=0.25×10−5⇒[H+]2=2.5×10−6⇒[H+]=√2.5×10−6=1.58×10−3 M≈1.6×10−3 M

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