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Question

The kinetic energies of a planet in an elliptical orbit about the sun at positions A, B and C are KA, KB and KC respectively. AC is the major axis and SB is perpendicular to AC at the position of the sun S as shown in the figure with SA<SB. Then,



A
KA < KB < KC
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B
KA > KB > KC
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C
KB <KA < KC
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D
KB >KA > KC
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Solution

The correct option is B KA > KB > KC
L = mvr = Iω = constantKinetic energy K =L22IIA<IB<ICKA>KB>KC

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