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Standard XII

Physics

Stopping Potential

The kinetic e...

Question

The kinetic energies of photoelectrons ejected from a metal surface by light of sufficient wavelength have range from 0 to $3.2 \times 10^{- 19}$ J. The stopping potential required will be equal to

2 V

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6.2 V

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4.2 V

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9 eV

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Solution

The correct option is A 2 V
$K_{m a x} = 3.2 \times 10^{- 19} s$
$= 2^{.} e V$
$I f V_{0} i s s t o p p i n g p o t e n t i a l,$
$e V_{0} = K_{m a x}$
$e V_{0} = 2.0 e V$
$V_{0} = 2 V$
So, the answer is option (A).

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Similar questions

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The kinetic energies of photoelectrons ejected from a metal surface by light of sufficient wavelength have range from 0 to 3.2×10−19 J. The stopping potential required will be equal to

The correct option is A 2 VKmax = 3.2×10−19s = 2.eVIf V0 is stopping potential,eV0= KmaxeV0= 2.0 eVV0= 2 VSo, the answer is option (A).

The kinetic energies of photoelectrons ejected from a metal surface by light of sufficient wavelength have range from 0 to $3.2 \times 10^{- 19}$ J. The stopping potential required will be equal to

The correct option is A 2 V
$K_{m a x} = 3.2 \times 10^{- 19} s$
$= 2^{.} e V$
$I f V_{0} i s s t o p p i n g p o t e n t i a l,$
$e V_{0} = K_{m a x}$
$e V_{0} = 2.0 e V$
$V_{0} = 2 V$
So, the answer is option (A).