Question

The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal, when displacement (amplitude = a) is

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

Suppose at displacement y from mean position kinetic energy = potential energy

$\Rightarrow \frac{1}{2}m(a^2-y^2)w^2=\frac{1}{2}m{w}^2{y}^2$
$\Rightarrow a^2=2y^2\Rightarrow y=\frac{a}{\sqrt{2}}$