The Kinetic energy 'K' of a particle moving along a circle of radius R depends on the distance covered 'S' as K=aS2. The force acting on the particle is
A
2aS2R
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B
2aS(1+S2R2)12
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C
2aS
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D
2aR2S
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Solution
The correct option is B2aS(1+S2R2)12 K=aS2;K=12mv2Fc=mv2R=2KR=2aS2RFt.dS=dK⇒Ft=dKds=2aSF=√F2c+F2t=√(2aS2R)2+(2aS)2=2aS√1+(SR)2