Question

The kinetic energy of $16$ grams of oxygen at ${27}^{o}C$ is:

• A. $400cal$
• B. $450cal$
• C. $1800cal$
• D. $200cal$

Answer 1

The correct option is B $450cal$

$K.E=\frac{3}{2}nRT$
$n=16/32=0.5moles$
$KE=\frac{3}{2}\times 0.5\times 2\times 300$
Thus, $KE=450cal$