Question

The kinetic energy of $1g$ molecule of a gas at normal temperature and pressure is :

• A. $1.3$ x ${10}^{2}J$
• B. $2.7$ x ${10}^{2}J$
• C. $0.56$ x ${10}^{4}J$
• D. $3.4$ x ${10}^{3}J$

Answer 1

The correct option is D $3.4$ x ${10}^{3}J$

There is no information about gas so the translational kinetic energy is given as,

$K=\frac{3}{2}RT$

$=\frac{3}{2}\times 8.31\times \left(273+0\right)$

$=3.4\times {10}^{3}J$

Thus, the kinetic energy of a gas molecule is $3.4\times {10}^{3}J$.