Question

The kinetic energy of $2.8g$ of nitrogen gas at ${127}^{\circ }C$ is nearly

• A. $2\times 249.3J$
• B. $2\times 200.4J$
• C. $2\times 25J$
• D. $20.5J\times 2$

Answer 1

Answer: (A)

$2\times 249.3J$

Using the formula,

$KE=\frac{3}{2}nRT=\frac{3}{2}\times \frac{2.8}{28}\times 8.314\times 400=498.84J$.